Solve tan2x(1-tan^(2)x=2/(2/root 3): 0-360

  • Thread starter Thread starter Sebastian999
  • Start date Start date
  • Tags Tags
    Trig
Click For Summary

Homework Help Overview

The problem involves solving the equation tan(2x)(1 - tan²(x)) = 2/(2/√3) within the interval of 0 to 360 degrees. The equation includes trigonometric functions and requires finding solutions based on the given constraints.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to clarify the equation's structure and the interpretation of the right-hand side. There is discussion about the simplification of the expression 2/(2/√3) and whether it should yield √3 or √2.

Discussion Status

The discussion is ongoing, with participants questioning the correctness of the simplifications and interpretations of the equation. There is no explicit consensus on the correct form of the equation or its components, but there is active engagement in exploring the assumptions involved.

Contextual Notes

Participants are navigating potential errors in the simplification process and are addressing the implications of these errors on the overall problem. The interval for solutions is specified as 0 to 360 degrees, which may influence the approach to finding solutions.

Sebastian999
Messages
2
Reaction score
0

Homework Statement


tan2x(1-tan^(2)x=2/(2/root 3) for interval 0 to 360

Find solutions to the equation


Homework Equations





The Attempt at a Solution

.
I know i can't make it equal to zero but yeah...
 
Physics news on Phys.org
Do you mean:

[tex](1-tan^2(x)) * tan(2x) = \frac{2}{\frac{2}{\sqrt{3}}}[/tex]
 
Sebastian999 said:

Homework Statement


tan2x(1-tan^(2)x=2/(2/root 3) for interval 0 to 360

Дьявол said:
Do you mean:

[tex](1-tan^2(x)) * tan(2x) = \frac{2}{\frac{2}{\sqrt{3}}}[/tex]
And
[tex]2/(2/root 3)= \frac{2}{\frac{2}{\sqrt 2}}= 2[/tex]
 
HallsofIvy said:
And
[tex]2/(2/root 3)= \frac{2}{\frac{2}{\sqrt 2}}= 2[/tex]

I believe this is incorrect... shouldn't it be the square root of 3, and not of 2?
 
Aureus said:
I believe this is incorrect... shouldn't it be the square root of 3, and not of 2?

And even then... it would be equal to [tex]\sqrt{2}[/tex] and not 2. Double brain fart :-p
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
Replies
10
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
3
Views
3K
  • · Replies 24 ·
Replies
24
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
3K