- #1
alejandrito29
- 150
- 0
i need to solve the follow diferential equation:
[tex](\frac{du}{dy})^2=A+Be^{2u}+C \sqrt{D+Ee^{4u}}[/tex]
where A,B,C,D,E are nonzero.
[tex](\frac{du}{dy})^2=A+Be^{2u}+C \sqrt{D+Ee^{4u}}[/tex]
where A,B,C,D,E are nonzero.