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## Homework Statement

There are two forces on the 2.43 kg box in the overhead view of the figure but only one is shown. For

*F*1 = 20.0 N,

*a*= 11.4 m/s2, and θ = 33.0°, find the second force

**(a)**in unit-vector notation and as

**(b)**a magnitude and

**(c)**a direction. (State the direction as a negative angle measured from the +x direction.)The acceleration is in the third quadrant.

## Homework Equations

So, I used F2 = m(a) - F1. To try and find Force 2 and used cos and sin to fine it in vector notation. Apparently I got that wrong, HELP!

## The Attempt at a Solution

I used cos and sin to fine it in vector notation. Apparently I got that wrong, HELP!

So for a I got F2 = 2.43 * 11.4 - 20 which resulted in 7.03 or something and pluged that into (7.03 sin 33 degrees) and to find (j) and did the same with cos to find (i)

It didn't work, and magnitude and direction ended up being wrong because a) was wrong HEEEELP

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