Solve the Physics Problem: Astronaut Drops Camera on Moon

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Homework Help Overview

The problem involves an astronaut dropping a camera from a height on the Moon, specifically from a 14.7 m cliff. The camera is released with zero initial speed and the discussion centers around determining how far it has fallen after a specified time, given its velocity at an earlier time.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss calculating the gravitational acceleration on the Moon and its implications for the problem. There are questions about the relationship between time, velocity, and displacement, as well as the correct application of kinematic equations.

Discussion Status

The discussion is ongoing, with participants providing different approaches to calculate the necessary values. Some guidance has been offered regarding the use of specific equations, but there is no clear consensus on the best method to proceed.

Contextual Notes

Participants express frustration over the complexity of the problem and the time spent on it. There is mention of needing to clarify the signs for acceleration and the initial conditions for displacement calculations.

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During a walk on the Moon, an astronaut accidentally drops his camera over a 14.7 m cliff. It leaves his hands with zero speed, and after 2.2 s it has attained a velocity of 3.3 m/s downward. How far has the camera fallen after 4.3 s?

I am so lost! I have no idea what to do! I would appreciate any help!
 
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First you have to calculate (or search) the gravity acceleration on the Moon:

g = G.M/R^2 (G: gravitational constant, M, R are the mass and radius of the Moon)

Then everything is straight forward.
 
then would i just multiply that answer by 4.3 for the time?
 
pixel01 said:
First you have to calculate (or search) the gravity acceleration on the Moon:

g = G.M/R^2 (G: gravitational constant, M, R are the mass and radius of the Moon)

Then everything is straight forward.

With the information he was given, the following formula is better:

http://en.wikipedia.org/wiki/Torricelli's_equation

Vy^2 = Vy0^2 + 2aD

Where: Vy is the final speed, Vy0 is the initial speed, a is the acceleration, D is displacement. a is the only unknown, so this should be fairly simple.
 
I am trying to find how far it has fallen. I assume the final speed is the 3.3m/s stated in the problem and the initial is 0m/s. The acceleration on the moon that I figured out from this equation was 1.6256. So should I solve for the displacement? I am so frustrated. I have been working on this since 6 o'clock and I only have half the assignment done.
 
Woops, I'm sorry, I thought you had the displacement from the first 2.2s...

With the only known information being the variation of speed and time, you should use:

Vy = Vy0 + a.t

Where t is time. With the moon gravity obtained (which must be negative, make sure you get the signs right, and I got -1.5m/s), you have to use another equation:

x = x0 + v0.t + 1/2.a.t^2

Where x0 and x are initial and final position, respectively. You should be able to do this now. Now the exercise asks for the position at 4.3s. Solve for x, and make x0 = 14.7m.
 

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