Velocity of a Dropped Camera on Mars

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SUMMARY

A robot probe drops a camera from a height of 235 meters on Mars, where the gravitational acceleration is 3.7 m/s². The final velocity of the camera upon impact with the ground is calculated using the equation v²f = v²i + 2aΔd. With an initial velocity (v²i) of 0 m/s, the final velocity (v²f) is determined to be approximately 41.7013 m/s. Including units in the final answer is essential for clarity and correctness.

PREREQUISITES
  • Understanding of kinematic equations, specifically v²f = v²i + 2aΔd
  • Basic knowledge of gravitational acceleration on Mars (3.7 m/s²)
  • Familiarity with units of measurement in physics (m/s)
  • Concept of free fall and its implications in a vacuum environment
NEXT STEPS
  • Study the application of kinematic equations in different gravitational fields
  • Explore the effects of atmospheric conditions on free fall in various planetary environments
  • Learn about the physics of motion in a vacuum
  • Investigate the design and function of robotic probes used in space exploration
USEFUL FOR

Students in physics, educators teaching kinematics, and engineers involved in space exploration and robotics will benefit from this discussion.

Casey314stl
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Homework Statement



A robot probe drops a camera off the rim of
a 235 m high cliff on Mars, where the free-fall
acceleration is 3.7 m/s^2

Find the velocity with which it hits the
ground.
Answer in units of m/s

Homework Equations



v^2f=v^2i+2aΔd

The Attempt at a Solution


41.7013
 
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Casey314stl said:

Homework Statement



A robot probe drops a camera off the rim of
a 235 m high cliff on Mars, where the free-fall
acceleration is 3.7 m/s^2

Find the velocity with which it hits the
ground.
Answer in units of m/s

Homework Equations



v^2f=v^2i+2aΔd

The Attempt at a Solution


41.7013

If you incude the units, that's correct.
 

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