Solve the trig equations 2sin^2(x) + sin(x) - 1 =0

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SUMMARY

The discussion focuses on solving the trigonometric equation 2sin²(x) + sin(x) - 1 = 0 within the interval 0 ≤ x ≤ 2π. Participants identify that the equation is quadratic in form, with sin(x) as the variable, and suggest using the quadratic formula to find solutions. The conversation emphasizes verifying the solutions by substituting them back into the original equation to ensure accuracy.

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Homework Statement



Find all values of x in the interval 0<=x<=2pi for which 2sin^2(x)+sin(x)-1=0.

Homework Equations





The Attempt at a Solution



I have no idea.

I spent awhile trying to figure it out on my graphics calculator but couldn't figure it out.

I have only been told how to solve trig equations where there is 1 trig function, lol.

any help would be great thanks.
 
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This equation is quadratic, the variable is sin(x). Can you solve now?
 
ax^2+bx+c=0

quadratic formula ...

for trig

x=trig identity
 
o rite i see.

I think I have the right answers lol

cheeers
 
Trail_Builder said:
o rite i see.

I think I have the right answers lol

cheeers
You can always check it by plugging it back into your original equation.
 

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