Solve Thermodynamics: 7.67 kg Lead & 764 g Water Boiling Pt

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SUMMARY

The discussion focuses on a thermodynamics problem involving 7.67 kg of molten lead and 764 g of water at 53.3°C. The key equation utilized is mc(ΔT) = m(water)c(ΔT) + m(vapor)Lv, which relates the heat transfer between the lead and water. Participants confirm that the physical change in the lead involves solidification as it cools, while the water may boil depending on the heat exchange. The solution requires calculating the heat lost by the lead and the heat gained by the water to determine how much water boils.

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  • Understanding of heat transfer principles in thermodynamics
  • Familiarity with specific heat capacity and latent heat concepts
  • Knowledge of phase changes, particularly melting and boiling points
  • Ability to manipulate and solve equations involving heat transfer
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  • Study the concept of latent heat and its application in phase changes
  • Learn about specific heat capacities of common substances, including lead and water
  • Explore the first law of thermodynamics and its implications in heat transfer problems
  • Practice solving similar thermodynamics problems involving heat exchange
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Homework Statement



Suppose 7.67 kg of molten (liquid) lead at its melting point is poured into 764 g of water at 53.3o C. How much of the water boils?

Homework Equations


mc(detla T) = m(water)c(detla T).


The Attempt at a Solution


i m guessing i have to do the dollowing:
mc(detla T) = m(water)c(detla T)+m(vapor)Lv
am i on the right track..
thanks in advance
 
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describe the physical change that occurs in the lead.
 

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