How much water boils when 7.67 kg of molten lead is poured into water?

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Homework Statement



Suppose 7.67 kg of molten (liquid) lead at its melting point is poured into 764 g of water at 53.3o C. How much of the water boils?

Homework Equations


mc(detla T) = m(water)c(detla T).


The Attempt at a Solution


i m guessing i have to do the dollowing:
mc(detla T) = m(water)c(detla T)+m(vapor)Lv
am i on the right track..
thanks in advance
 
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