Solve Thin-Lens Equation: Prove u=v, Find Focal Length Change

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SUMMARY

The discussion focuses on solving the Thin-Lens Equation to demonstrate that when an object is positioned at twice the focal length from a converging lens, the image produced is of equal size to the object. The algebraic proof shows that if u = 2F, then v equals u, confirming that the image distance equals the object distance. Additionally, for a convex lens with a focal length of 5cm, the lens must be moved 45cm to adjust focus from the nearest object at 50cm to distant objects at infinity.

PREREQUISITES
  • Understanding of the Thin-Lens Equation
  • Familiarity with focal length concepts
  • Knowledge of object distance (u) and image distance (v)
  • Basic principles of optics and lens behavior
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  • Study the derivation of the Thin-Lens Equation
  • Learn about the properties of convex lenses
  • Explore the concept of similar triangles in optics
  • Investigate practical applications of lens adjustments in photography
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Students of optics, physics educators, and photography enthusiasts seeking to understand lens mechanics and image formation principles.

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Question
i)
Prove that if an object is at a distance of twice the focal length from a converging lens, the image is the same size as the object. Show this using an algebraic method.

Possible Answer
Must prove u = v
2F = U
2/u + 2/v = u
u + v = 2u
v=u

ii)
A small hand-held camera has a convex lens with a focal length of 5cm. The camera is arranged so that by moving the lens in and out, objects from 50cm away to "infinity" (very remote objects like mountains and scenery) can be brought to an exact focus on the film. How many centimeters will the lens have to be moved as the focus is changed from the closest to the farthest object?

Possible Answer:
Well, F = 5cm
U = 50cm
No I can't do this, could someone explain it please.
 
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The solutions for both of these questions involve the thin lens equation. For (i) using the object distance and focal lenth will allow you to solve for the image distance. Then using a similar triangle argument you can show that the two heights are the same.

For (ii), find the image distances for each of the the two distances (50cm and infinity). Since objects at 50cm are the nearest objects that can be imaged, the flim must be located this far away from the lens... Hopefully this will start you along the right track.
 

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