Solve Trajectory Motion Homework: Find t, Drop Apple to Pierce Arrow

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Homework Help Overview

The problem involves projectile motion, specifically analyzing the trajectory of an arrow shot at an angle and determining the timing for an apple dropped from a height to intersect with the arrow's path. The context includes calculating the time of flight for the arrow and the timing for the apple drop relative to the arrow's flight.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss using kinematic equations to relate horizontal and vertical motion, with attempts to isolate variables such as time and initial velocity. Some express confusion over handling multiple unknowns in the equations.

Discussion Status

There is ongoing exploration of the relationships between the variables involved in the projectile motion. Some participants have provided insights that clarify the approach to solving for time and velocity, while others are still grappling with how to incorporate the angle of projection into their calculations.

Contextual Notes

Participants note the specific conditions of the problem, including the requirement that the apple be dropped from a height of 6.0 meters directly above the arrow's impact point. There is also mention of the assumption that the arrow and apple would hit the ground simultaneously if there were no angle involved.

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Homework Statement

Hi, I have been working on this problem for a while, and cannot figure it out. Heres the question.

An arrow is shot at an angle of theta = 45 degrees above the horizontal. The arrow hits a tree a horizontal distance D = 220m away, at the same height above the ground as it was shot. Use g = 9.8m/s^2 for the magnitude of the acceleration due to gravity

a.)Find t, the time that the arrow spends in the air.
b.)Suppose someone drops an apple from a vertical distance of 6.0 meters, directly above the point where the arrow hits the tree. How long after the arrow was shot should the apple be dropped, in order for the arrow to pierce the apple as the arrow hits the tree?

Homework Equations


Vx = Vcos(theda), x= Vt



The Attempt at a Solution



a.) a = 2x / t^2, 9.8 = 2(220cos45) / t^2, t = 5.6

5.6 is not the right answer. Thanks for your time.
 
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So we'll need to equations ...

x=(v_0\cos\theta)t

Solve for initial velocity in the x, then plug that in y=(v_0\sin\theta)t-\frac{1}{2}gt^2 and solve for t.
 
Thanks for your response,but I still can't get it. With the equation x = Vcos(theda)t there is 2 unknowns, time and velocity. I don't understand how to manipulate the equation so my info fits. Thanks for your time.
 
Solving for velocity in the x ...

v_0=\frac{x}{t\cos\theta}

Plugging into y ...

y=\frac{x}{t\cos\theta}(\sin\theta)t-\frac{1}{2}gt^2

In your problem ... "at the same height above the ground as it was shot" so y=0.

Solve for t.
 
Ah, it finally makes sense. Thanks for your reply, it really helped.

On part b i left out part of the question on accident. It said that "Suppose someone drops an apple from a vertical distance of 6.0 meters, directly above the point where the arrow hits the tree." How long after the arrow was shot should the apple be dropped, in order for the arrow to pierce the apple as the arrow hits the tree?

I know that if there was no angle,then these would hit the ground at the same time, regardless of the velocity. But since there is an initial angle, how do I take that into account for my problem. Thanks again for your help.
 

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