Solve Transposing Formula: Rs = Rm x Im/I

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Homework Help Overview

The discussion revolves around the problem of transposing a formula to make Rs the subject. The context involves electrical circuits, specifically dealing with shunt resistance in relation to current measurements.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the equation I_m = I x Rs/(Rm + Rs) and discuss the challenges of having Rs appear multiple times. There are questions about the correct interpretation of the equation and the necessity of parentheses for clarity.

Discussion Status

The conversation is ongoing, with participants providing guidance on how to approach the problem. Some express uncertainty about their mathematical skills and seek clarification on the steps needed to isolate Rs.

Contextual Notes

There is mention of specific values for current and resistance, which may influence the calculations, but the exact numerical context is not fully resolved. Participants also note the importance of correct notation and understanding of mathematical operations in this context.

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Homework Statement


Make Rs the subject when I am = I x Rs/Rm+Rs.


Homework Equations





The Attempt at a Solution

Rm x Im/I = Rs. I don`t think this answer is correct. Whats throwing me is the fact that the subject appears twice in the equation. Any guidance would be appreciated.
 
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brenfox said:

Homework Statement


Make Rs the subject when I am = I x Rs/Rm+Rs.
I'm almost certain that you are missing parentheses.

Is this your equation?
$$I_m = I * \frac{R_s}{R_m} + R_s $$

If it isn't, then add parentheses to make your meaning clear.
brenfox said:

Homework Equations





The Attempt at a Solution

Rm x Im/I = Rs. I don`t think this answer is correct.
Probably not, but I can't tell what you did to get this.

Start with the equation you're given and show what you're doing at each step to get a new equation.
brenfox said:
Whats throwing me is the fact that the subject appears twice in the equation. Any guidance would be appreciated.
 
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The question i`am given is is this: Determine the required value of the shunt resistance if the maximum value of the current I is 200A. The meter can read a maximum of 1mA and has a resistance of 0.1Ω.
The relevant equation I think is this : I am = I x Rs/ Rm + Rs.
The question asks for the shunt resistance therefore i am required to transpose and make Rs the subject.
Now, my maths is not yet to the required standard and to make Rs the subject is confusing me due to the fact that it appears twice in the equation. Do i start by cancelling both Rs out of the equation? My first step would be to move I over so it would be I/Im = Rs/Rm+Rs. Not sure on my next move though.
 
brenfox said:
The question i`am given is is this: Determine the required value of the shunt resistance if the maximum value of the current I is 200A. The meter can read a maximum of 1mA and has a resistance of 0.1Ω.
The relevant equation I think is this : I am = I x Rs/ Rm + Rs.
Please carefully read what I wrote earlier. Your equation probably doesn't what you think.

This is what you wrote:
$$I_m = I * \frac{R_s}{R_m} + R_s$$

Is that what you meant? If not, use parentheses as necessary.



brenfox said:
The question asks for the shunt resistance therefore i am required to transpose and make Rs the subject.
Now, my maths is not yet to the required standard and to make Rs the subject is confusing me due to the fact that it appears twice in the equation. Do i start by cancelling both Rs out of the equation?
No, and it would probably be useful if you removed "canceling" from your vocabulary. It has a very specific meaning that you apparently don't understand.
brenfox said:
My first step would be to move I over so it would be I/Im = Rs/Rm+Rs. Not sure on my next move though.
Is this your starting equation?
$$I_m = I * \frac{R_s}{R_m + R_s} $$

If so, you need parentheses around the two terms in the denominator, like this:
Im = I * Rs/(Rm + Rs).

For this type of equation, you can use these operations:
  • Add the same quantity to both sides of the equation.
  • Subtract the same quantity from both sides of the equation.
  • Multiply both sides of the equation by the same quantity.
  • Divide both sides of the equation by the same quantity.

I'm hopeful you won't use the word "cancel".
 
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Are you going to give it a shot?
 

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