Solve Using Conservation of Energy

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SUMMARY

The discussion focuses on solving a physics problem using the conservation of energy principle. The spool has a mass of 50 kg and a radius of gyration of 0.280 m, while the block A weighs 20 kg. The goal is to determine the distance the block must fall for the spool to achieve an angular velocity of 5 rad/s and to calculate the tension in the cord during the block's motion. The relevant equations include the conservation of energy formula, which incorporates gravitational potential energy and kinetic energy of both the block and the spool.

PREREQUISITES
  • Understanding of conservation of energy principles in physics
  • Familiarity with rotational dynamics and angular velocity
  • Knowledge of basic kinematic equations
  • Ability to manipulate equations involving mass, radius of gyration, and gravitational force
NEXT STEPS
  • Study the derivation of the conservation of energy equation in rotational motion
  • Learn how to calculate angular velocity from linear velocity using the formula V = ωR
  • Explore the relationship between tension in a cord and the forces acting on a falling mass
  • Investigate the effects of neglecting mass in cord tension calculations
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators looking for practical examples of rotational dynamics applications.

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Homework Statement



Solve Using Conservation of Energy

The spool has a mas of 50 kg and a radius of gyration k(o) = .280m. If the 20 kg block A is released form rest, determine the distance the block must fall in order for the spool to have an angular velocity w = 5 rad/s. Also what is the tension in the cord while the block is in motion? Neglect the mass of the cord


Homework Equations





The Attempt at a Solution



T1 + V1 + T2 + V2

Does V1 = 0 because it is at rest from the start

T1 = .5mv2 + .5Iw2 = .5*20*0 + .5*50*.282 = 1.96

V2g = Wy (y is what I am looking for but how do i calculate work W)
V2e = .5ks2 = .5*.28*s2 = .14s2

T2 = .5*20*v2 + .5*50*.282 = 10v2 + 1.96

1.96 = Wy + .14s2 + 10v2 + 1.96



To answer the question "determine the distanc ethe block must fall" means solve for y right

To answer the question "what is the tension of the cord" means solve for s right

How do i find v
 
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The distance the block falls is your energy..

What does that go into?

m_b*g*h = 1/2*m_b*V2 + 1/2*m_s*R_s22

V = ω*R_s

So h is what you are solving for and I think that looks like ...

h = 1/2*ω2R_s2*(m_b + m_s)/(g*m_b)
 

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