Solve Vector v as Linear Combination of x & y

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SUMMARY

The discussion focuses on expressing the vector v = [14 -12]^T as a linear combination of the vectors x = [2 -1]^T and y = [-1 3]. The initial approach of row reducing the matrix formed by x and y was incorrect, as it led to confusion regarding the relationship between the reduced form and the original vectors. The correct method involves setting up a system of equations based on the linear combination, resulting in the equations 2α - β = 14 and -α + 3β = -12, which can be solved for α and β to find the coefficients for x and y.

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mr_coffee
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Okay this problem seems easy, and i t hought i understood how to do it, but no.

Express the vector v= [14 -12]^T as a linear combination of:
x = [2 -1]^T; y = [-1 3];
v = _x + _y;
_ means that's were they want me to put an answer.

So i row reduced
2 -1
-1 3
which is
1 0
0 1

so why wouldn't the answer just be
v = 14x -12y

because
14 * [1 0] = [14 0];
-12*[0 1] = [0 -12];
which is [14 -12] if u add them so what the?
 
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Because x and y are NOT [1, 0] and [0,1]! Saying that the "row-reduce" to [1,0] and [0,1] does not mean they are equal to them.

I would suggest not row reducing at all:
[tex]\alpha x+ \beta y= [2\alpha, -\alpha]+ [-\beta,3\beta][/tex]
[tex]= [2\alpha- \beta,-\alpha+ 3\beta]= [14, -12][/tex]
so you must have [itex]2\alpha- \beta= 14[/itex] and [itex]-\alpha+ 3\beta= -12[/itex]. Can you solve those two equations?
 
Ahhh, i c, thank you Ivy! It worked out great!
 

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