Solve Velocity Function: Distance in 0-5 Interval

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SUMMARY

The discussion focuses on solving the velocity function v(t) = 3t - 11 for a particle moving along a line within the time interval of 0 to 5 seconds. The primary goal is to calculate the distance traveled by the particle during this interval. The user initially miscalculated the velocity at t=5, resulting in an incorrect value. The correct approach involves finding the anti-derivative of the velocity function to determine the position function x(t), which will then allow for the calculation of distance.

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  • Understanding of calculus concepts, specifically anti-derivatives.
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  • Study the process of finding anti-derivatives in calculus.
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Hello, I need help on this following problem on velocity

Homework Statement



The velocity function (in meters per second) is given for a particle moving along a line.

v(t)=3t-11, 0 (greater than or equal to) t (greater than or equal to) 5

Find the distance (in meters) traveled by the particle during the given time interval

Homework Equations



v(t)=3t-11, 0 (greater than or equal to) t (greater than or equal to) 5

The Attempt at a Solution



I tried the following:
3(5)-11=4

But it isn't correct.

I know I have to find the anti-derivative of v(t).

How would I find t? Do I have to do the derivative of v(t) to find acceleration? Would that help me do this problem?

Can someone help me with this problem?

Thanks

Edit: I figured out this answer. Thanks.
 
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