Solve Wave Problems: Calculating Length for Higher Note on Slide Whistle

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Homework Help Overview

The discussion revolves around calculating the length of a slide whistle needed to produce a note one octave higher than its current length of 27 cm. The subject area includes wave physics and sound frequency relationships.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between frequency and wavelength when moving up an octave, questioning how these changes affect the length of the whistle. There are attempts to clarify the implications of doubling frequency and halving wavelength.

Discussion Status

Some participants have provided insights into the relationship between frequency and wavelength, noting that the length of the whistle is related to these changes. There is ongoing exploration of the correct length calculation, with references to relevant equations and concepts from their studies.

Contextual Notes

Participants reference specific equations related to wave behavior in tubes, indicating a need to apply these to the problem at hand. There is mention of potential confusion regarding the application of these concepts to the specific scenario of the slide whistle.

manda
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Homework Statement


A slide whistle has a length of 27 cm. If you want to play a note one octave higher, the whistle should be how long?

Homework Equations



velocity=(wavelength)*(frequency)
speed of sound= 343 m/s

The Attempt at a Solution



343=6.75f
50.8=f

50.8*2= 101.63Hz

( i am so lost)
 
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Q#1: What happens to the frequency when something goes one octave higher?
Q#2: What happens to the wavelength when {insert answer to Q#1 here} happens to the frequency?
 
it doubles?
 
Yes. What happens to the wavelength when the frequency doubles?
 
it halves?

so is the answer 101.63? or 27/2?
 
manda said:

Homework Statement



A slide whistle has a length of 27 cm. If you want to play a note one octave higher, the whistle should be how long?

Homework Equations



velocity=(wavelength)*(frequency)
speed of sound= 343 m/s

The Attempt at a Solution



343=6.75f
50.8=f

50.8*2= 101.63Hz

( i am so lost)


Hi Manda, I saw you cry for help. I'll give it a shot.

An octave is the interval between one musical pitch and another with half or double its frequency. For example, if one note has a frequency of 400 Hz, the note an octave above it is at 800 Hz, and the note an octave below is at 200 Hz.

Further octaves of a note occur at 2^n times the frequency of that note (where n is an integer), such as 2, 4, 8, 16, etc. and the reciprocal (1/2^n) of that series. For example, 50 Hz and 400 Hz are one and two octaves away from 100 Hz because they are ½ (or 2^−1) and 4 (or 2^2) times the frequency, respectively.

So first calculate the lowest frequency of the note in the whistle, using your relevant equations, as well as the length of the whistle. Then double that frequency to get the octave one higher. Let me know if I should clarify. ~M
 
Last edited by a moderator:
Yes. One of those two is correct; which is referring to a length? (Since the question is asking for a length).

p.s. It might also help to find the equation involving whistle (or tube) length. Is there a discussion on tubes in your book, in the chapter dealing with sound or waves?
 
27/2

umm yeah there is 2 paragraphs
all they say is open = Y/2
closed=y/4 and then y/2


does that sound right?
 
Yes, that's right. In all those cases, the tube length is proportional to the wavelength.
So when the wavelength halves, the tube length _____ ?
 

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