Solve Work Formula Problem: Calculate Force Exerted by Man

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To calculate the force exerted by the man pushing against the piano, the correct approach involves considering both the gravitational force acting down the incline and the frictional force. The gravitational force is calculated using F = mgsin(theta), resulting in 3237.3 N. However, this calculation does not account for the frictional force, which opposes the motion and must be included to determine the total force exerted by the man. The effective coefficient of kinetic friction of 0.40 plays a crucial role in this calculation, as it reduces the net force the man needs to exert. Therefore, the final force exerted by the man must include both the gravitational component and the frictional force to ensure the piano does not accelerate.
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I have pretty much figured out the problem, but i am unsure of my work.
the question reads:
a 330kg piano slides 3.6m down a 28degree incline and is kept from accelerating by a man who is pushing back on it parallel to the incline. The effective coefficient of kinetic friction is 0.40. Calculate: (a) the force exerted by the man.

F=mgsin(theta)
=(330kg)(9.81m/s2)sin90
F= 3237.3 N

Is this the correct formula to use to find the force exerted by the man?
 
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Where is the force due to the friction? The man's job is made easier by the help of friction.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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