Solve Work on Inclined Plane for m1, a, h, m2, uk

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Homework Help Overview

The discussion revolves around a physics problem involving two blocks, one on an inclined plane and the other hanging, connected by a cord over a pulley. The problem includes calculating the work done by various forces on each block as they move a certain distance, considering factors like mass, angle of incline, and kinetic friction.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the work done on each block, including gravitational and frictional forces. There are attempts to derive expressions for total work and final speed, with some questioning the assumptions made about the system's dynamics and the role of kinetic friction.

Discussion Status

Some participants have provided detailed calculations and expressions for work done on each block, while others are seeking clarification on the correctness of their approaches. There is an ongoing exploration of the implications of constant speed in the context of the problem.

Contextual Notes

Participants note the importance of adhering to posting guidelines and the need for clear communication in the forum. There are references to previous posts and the need to maintain focus on the physics problem at hand.

oreosama
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Homework Statement


A block of mass m1 is placed on an inclined plane with slope angle a and is connected to a second hanging block of mass m2 by a cord passing over a small frictionless pulley the coefficient of kinetic friction is uk the system is released from rest with block m2 dropping a distance h.

given m1, a, h, m2, uk
calc the work due to each of the forces on block 1 in moving h
calc the work due to each of the forces on block 2 in moving h
calc the total work on the sys and final speed of the blocks

Homework Equations



w = F*d

The Attempt at a Solution



http://i.imgur.com/IxtPw.png

for block1

Wg = -h*mg*sin a

Wt1 = hT

Wn=0

Wff = -h*uk*mg*cos a

Wtot = hT - *mg*sin a - h*uk*mg*cos a


for block2

Wg = mgh

Wt = -hT

Wtot = mgh - hT


hT - *mg*sin a - h*uk*mg*cos a + mgh - hT = 1/2*m*Vf^2 + 1/2*m2*Vf^2 - 0 (start from rest)

sqrt( 2/(m1+m2) * (mg*sin a - h*uk*mg*cos a + mgh)) = Vf



----

blocks a, b, c are connected as shown. block a,b,c have same mass m and coefficient of kinetic friction between each block and the surface is uk. block c descends with constant velocity. use 30 for angle of incline. given m h uk determine

work due to forces on A moving h
work due to forces on B moving h
work due to forces on C moving h
solve for uk in terms of the other givens for the system to move at constant speed



http://i.imgur.com/DtwxJ.png


block A

Wff= -uk*mg*h

Wt= T1*h

block B

Wt2 = T2*h
Wg = -mg*sin a*h
Wff= -uk*mg*cos a * h
Wt1 = -T1*h

wtot = T2*h - mg*sin a * h - uk*mg*cos a * h - T1* h

block C

Wg = mg*h
Wt2 = -T2*h

Wtot = mg*h - T2*h


T1*h - uk*mg*h + T2*h - mg*sin a * h - uk* mg* cos a * h - T1*h + mg*h - T2*h = 0(constant speed implies vf v0 are the same meaning no change in kinetic energy right??)

-uk*mg*h - uk*mg*cos a * h = mg*sin a * h - mg*h

-uk - uk*cos a = sin a - 1

-uk(1 + cos a) = sin a - 1
uk = - (sin a - 1/ (1+cos a))

uk = 1/2 / (2+sqrt(3))/2

uk = 1/(2+sqrt(3))






want to be sure I am not doing anything horribly wrong thanks for any help.
 
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oreosama said:

Homework Statement


A block of mass m1 is placed on an inclined plane with slope angle θ and is connected to a second hanging block of mass m2 by a cord passing over a small frictionless pulley. The coefficient of kinetic friction is μk. The system is released from rest with block m2 dropping a distance h.

given m1, θ, h, m2, μk
calc the work due [STRIKE]to[/STRIKE] by each of the forces on block 1 in moving h
calc the work due to each of the forces on block 2 in moving h
calc the total work on the sys and final speed of the blocks

http://i.imgur.com/IxtPw.png
...

----

blocks a, b, c are connected as shown. block a,b,c have same mass m and coefficient of kinetic friction between each block and the surface is uk. block c descends with constant velocity. use 30 for angle of incline. given m h uk determine

work due to forces on A moving h
work due to forces on B moving h
work due to forces on C moving h
solve for uk in terms of the other givens for the system to move at constant speed

http://i.imgur.com/DtwxJ.png
...

want to be sure I am not doing anything horribly wrong thanks for any help.

Wow! A little bit of punctuation, etc. sure helps ! ...along with a few other changes.
 
didnt seem to be an issue on other posts, sorry
 
oreosama said:
didnt seem to be an issue on other posts, sorry
Do you mean, in your other posts?

In many of those you did, at least, use periods.

You probably should take a bit of time to read rules for posting in this Forum. Here are two short excerpts.
General Posting Guidelines
...Pay reasonable attention to written English communication standards. This includes the use of proper grammatical structure, punctuation, capitalization, and spelling. ...

Do not hijack an existing thread with off-topic comments or questions--start a new thread.
 
are you having trouble interpreting what I've typed? clearly not or you wouldn't be capable of correcting it by replacing one word and telling me to use more periods. I think that fulfills reasonable english communication.

now read the last sentence of your post. do you not see the irony?
 

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