Solve y=f(x): Range of f & Verify x in terms of y

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Homework Help Overview

The discussion revolves around solving the equation y=f(x) for x, specifically with the function f(x) = sqrt(x/(4-x)). Participants are exploring the range of f and how it relates to the domain of the original function.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the correctness of the expression x = 4y^2/(1+y^2) and its implications for the range and domain of the function. There is also a consideration of the relationship between the domain and range when dealing with inverses.

Discussion Status

Some participants have confirmed the correctness of the derived expression for x in terms of y. There is ongoing exploration of the range and domain, with differing interpretations being discussed. Guidance has been offered regarding terminology and the nature of the mappings involved.

Contextual Notes

Participants are considering the implications of the function's domain and range, particularly in relation to the original function and its inverse. There is mention of earlier parts of the question that involved finding the domain.

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Homework Statement




Solve y=f(x) for x. What is the range of f? Your expression for x in terms of y may be helpful to verify your statement.

f(x) = sqrt(x/(4-x))

Homework Equations





The Attempt at a Solution




I solved for x and got x = 4y^2/(1+y^2). I would like to know if this is correct or not also would the range of this be the domain of the original function because we had to find the domain in an earlier part of the question.
 
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[itex]x=4y^2/(1+y^2)[/itex] is correct. What are the range and domain of this mapping? You should be able to see that this does not match the domain and range of the original function.
 
i thought that doing this would give me the inverse though and that with an inverse the domain and range are switched
 
Two numbers satisfy the equation [itex]y^2=x[/itex] for positive x. Only one of these two numbers satisfies [itex]y=\sqrt x[/itex].
 
ah I see thank's a ton :). Would the domain be all real positive numbers and 0; and would the range be all reals ?
 
Correct. BTW, a shorter way to say "all real positive numbers and 0" is "the non-negative reals".
 
thank you DH you're helping me a ton tonight.
 

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