Solved Faraday's Law Problem: Find Correct Answer

  • Thread starter Thread starter neelakash
  • Start date Start date
  • Tags Tags
    Faraday's law Law
Click For Summary

Homework Help Overview

The problem involves a thin insulating ring with a uniform charge, rotating in a magnetic field. The context is centered around Faraday's law and its implications for induced electric fields and angular momentum.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to determine the correct angular velocity of the ring based on the effects of the induced electric field and torque. Some participants question the relationship between the induced electric field and the resulting angular momentum.

Discussion Status

Participants are exploring the implications of Faraday's law and the resulting dynamics of the system. There is an ongoing discussion about the correct interpretation of the induced electric field and its effect on the ring's motion, with some guidance provided regarding the integration of torque over time.

Contextual Notes

The original poster expresses concern about their answer choice during an exam, indicating a high-stakes context for the discussion. There is a mention of specific answer choices that have been considered and rejected.

neelakash
Messages
491
Reaction score
1
[SOLVED] Faraday's law problem

Homework Statement



Charge Q is uniformly glued over a thin (insulating) ring of radius R and mass m.The ring can rotate freely in horizontal plane about z axis.A magnetic field B is switched on along +z axis.The ring rotates with angular velocity w.

(A)w=0

(B)w= -(QB/2m)

(C)w= -(QB/m)

(D)w=(3/5)(QB/m)

Homework Equations


The Attempt at a Solution



I have rejected (A) and (D).Either (B) or (C) is correct...But,anyhow I cannot get the answer.Everytime I am ending up with dB/dt from Faraday's law...

Can anyone say what is correct?
 
Physics news on Phys.org
There'll be an electric field induced, so what's the torque due to the electric field on the ring? And so, what's the angular momentum imparted to the ring? The \frac{dB}{dt} will come up, but remember you're going to integrate over time to find the net angular momentum imparted.
 
Last edited:
If you do not mind,can you please only give me the answer?

I wrote (B) in an exam today...And I am really tensed about it...
 
OK,I am trying.
 
Last edited:
The answer is (B), cause
\tau= \frac{Q}{2 \pi} \int E.dl = - \frac{QR^2}{2} \frac{dB}{dt}
and L=\int \tau dt = I \omega
 
Last edited:
Thank you very much...

Oh...I was getting crazy over it...
 

Similar threads

Replies
5
Views
2K
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
6
Views
3K
Replies
1
Views
3K
Replies
2
Views
2K
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
2
Views
2K