Solving 0 in Physics E&M Equation

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Homework Help Overview

The discussion revolves around a physics problem from a calculus-based Electricity and Magnetism course, specifically dealing with an equation set to zero involving rational expressions. Participants are exploring methods to solve for the variable x in the equation E = 0 = 10 / (1 - x)² + 5 / x² - 10 / (1 + x)².

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the approach of combining fractions to simplify the equation. There is also mention of using numerical methods such as Newton's Method and questioning the appropriateness of such methods for a general physics course. Some participants express uncertainty about the best way to proceed, considering the complexity of the equation.

Discussion Status

The discussion is active, with participants offering suggestions for simplifying the equation and exploring different methods for finding solutions. There is no explicit consensus on the best approach, but some guidance has been provided regarding combining fractions and considering numerical methods.

Contextual Notes

Participants note the potential complexity of the problem and express concern over the use of advanced methods like Newton's Method in a basic physics context. There is also a mention of a solutions manual that provides a numerical answer, which raises questions about the methods used in the course material.

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I am working on a physics problem from a calc-based E&M (intro) course, and I came up with the following equation:

E = 0 = 10 / (1 - x)2 + 5 / x2 - 10 / (1 + x)2

I got here and worried it was a dead end, so I checked the solutions manual, and they have the exact same thing, and then say " therefore, the root is bla. So, ~equation~ = 0 => x = bla"

How did they solve this? =|

edit: The only attempt I would know how to make is solve one of the terms individually, and then solve the other two as a system, and hope that one of the two solutions coincide. However, this seems stupid because that basically leaves it all to chance.
 
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Hi anonymity! :smile:

Put the fractions on the same denominator and add them up. That's always a good first step!
 
Not a major point, but your title is screwy. You never "solve for zero." We know what zero is. You're solving for x, which is not known.
 
Yeah I know I read that as I was closing out the window to head to class..didn't have time or motivation enough to edit it, as it is irrelevant and clarified in my post.

Micro: thanks ill try that, seems like it could get very messy very quick though : I
 
anonymity said:
I am working on a physics problem from a calc-based E&M (intro) course, and I came up with the following equation:

E = 0 = 10 / (1 - x)2 + 5 / x2 - 10 / (1 + x)2

I got here and worried it was a dead end, so I checked the solutions manual, and they have the exact same thing, and then say " therefore, the root is bla. So, ~equation~ = 0 => x = bla"

How did they solve this? =|

edit: The only attempt I would know how to make is solve one of the terms individually, and then solve the other two as a system, and hope that one of the two solutions coincide. However, this seems stupid because that basically leaves it all to chance.
Did they give a formula, or a numerical answer? If they gave a formula, what is it?

If they give a formula they might have used the general solution of a quartic equation as given in http://en.wikipedia.org/wiki/Quartic_function , for example. If they gave a numerical answer they might have used Newton's Method.

RGV
 
It was a numerical value. I can't believe I didnt think of using Newton's method (i can't believe, either, that this actually showed up in a class other than basic single variable calculus...).

As far as if this is the way the book did it, I am not so sure. It seems unlikely that they would REQUIRE you to use something as obscure as Newton's method for a general physics course.

Regardless, assuming Newton's method doesn't fail and bounce all around the number plane, it will work. I will ask my professor tomorrow if there's a less tedious/more basic way to solve it.

Thanks for your help Ray.
 

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