Solving 0x10 + 0xfe: What's the Answer?

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SUMMARY

The discussion clarifies the addition of 8-bit unsigned hexadecimal values, specifically 0x10 + 0xfe, which equals 0x0e (decimal 14). The prefix "0x" denotes hexadecimal notation, and the range for 8-bit unsigned values is from 0 to 255. The conversation emphasizes that the result is influenced by overflow behavior rather than a reset, as demonstrated with additional examples using 16-bit values. The key takeaway is understanding how hexadecimal addition operates within the constraints of 8-bit representation.

PREREQUISITES
  • Understanding of hexadecimal notation and the significance of the "0x" prefix.
  • Knowledge of 8-bit unsigned integer limits and overflow behavior.
  • Familiarity with basic arithmetic operations in different numeral systems.
  • Concept of binary addition and its implications in computing.
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  • Study the principles of binary arithmetic and overflow in computing.
  • Learn about hexadecimal to decimal conversion techniques.
  • Explore 16-bit unsigned integer operations and their differences from 8-bit operations.
  • Investigate how different programming languages handle numeric overflows.
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Computer science students, software developers, and anyone interested in understanding hexadecimal arithmetic and its applications in programming and digital systems.

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Question: With 8-bit unsigned values, 0x10 + 0xfe =
Answer: 0x0e, which is decimal 14.What I know;
The prefix 0x is used in code to indicate that the number is being written in hex. Base 16.
I also am aware that with 8-bit unsigned values it goes from a range of 0 to 255.

Need help with:
Is this working? 10+f = (10+15, the base system is 16 so this is bigger so resets?) 0?
0+e(14)=14, meaning 0x0e I have probably done the working wrong so that's why I need help. Thanks.
 
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Hint: if you use 16bit -
1) 0x10 + 0xfe = 0x10e
2) 0x20 + 0xfe = 0x11e
And in 8 bit:
1) 0x10 + 0xfe = 0x0e
2) 0x20 + 0xfe = 0x1e
So it is more about overflow than reset.
 

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