Solving 1.5 Moles Monatomic Ideal Gas at 314K - No Calc

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The discussion centers on the isothermal compression of 1.5 moles of a monatomic ideal gas at 314K, initially occupying a volume of 3m³ and compressed to a final volume of 1m³. The key conclusion is that to determine the heat removed from the gas, one must understand that the change in internal energy (ΔU) is zero, leading to the equation Q = -W. However, calculating work (W) requires knowledge of the area under the P-V curve, which is not feasible without calculus, as algebra-based methods do not provide sufficient justification for the equations used.

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  • Understanding of ideal gas laws
  • Knowledge of thermodynamic principles, specifically isothermal processes
  • Familiarity with the concept of internal energy in thermodynamics
  • Basic calculus for understanding area under curves
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This discussion is beneficial for physics students, thermodynamics enthusiasts, and anyone seeking to deepen their understanding of gas laws and isothermal processes in thermodynamics.

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1. 1.5 moles of a monatomic ideal gas is enclosed at 314K. THe initial volume of the gas is 3m^3. The gas is comperssed isothermally to a final volume of 1m^3. How much heat is removed from the gas.



So deltaU=0, Q=-W, So we have to know the area under the P-V curve, but how can we get the solution without calculus?
 
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We can't. Algebra-based textbooks just provide the appropriate equation and justify it by saying that it can obtained by using calculus.
 

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