Solving 2^x=7·5^x with logarithms

[chjopl]

2^x=7*5^x
I know you have to take ln of both sides but i am having trouble doing that for the right side.

 

[shmoe]

Remember the property of logarithms, ln(ab)=ln(a)+ln(b). That should help you deal with the right hand side.

 

[dextercioby]

2^x=7*5^x
I know you have to take ln of both sides but i am having trouble doing that for the right side.

I could give u the only hint possible,but that would be useless.So i'll better show u my version.Logarithmate both sides of the equation to find:
$$x\ln 2=\ln 7+x\ln 5 =>x=\frac{\ln 7}{\ln 2-\ln 5}$$.

Okay...??Clear?

PS:Shmoe,u were quicker than me...Again.

 

[chjopl]

Yeah thanks a lot i was messing up and having ln7*xln5