Solving 3r(r+1)=r(r+1)(r+2)-r(r-1)(r+1) and Finding r(r+1) Sum

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SUMMARY

The equation 3r(r+1) is proven to be equal to r(r+1)(r+2) - r(r-1)(r+1) through algebraic manipulation. By expanding the right-hand side and factoring, one can demonstrate the equality. Additionally, to find the total sum of r(r+1), it is essential to recognize that each 'r' term on the right is one less than the corresponding term on the left. This understanding aids in simplifying the expression effectively.

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Harry2
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Hey,
Please may someone help me.
How can I show that 3r(r+1) is equal to r(r+1)(r+2) - r(r-1)(r+1) and then I would find the total sum of r(r+1).
Thanks in advance for any help.
 
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Have you tried expanding r(r+1)(r+2) - r(r-1)(r+1)?

To find the sum, notice that each 'r' term on the right is 1 less than an 'r' term on the left.
 
To show:

$$3r(r+1)=r(r+1)(r+2) - r(r-1)(r+1)$$

try factoring the RHS. :)
 
MarkFL said:
To show:

$$3r(r+1)=r(r+1)(r+2) - r(r-1)(r+1)$$

try factoring the RHS. :)

I just thought you couldn't use the right hand side first because it was a show that question. Thanks both of you!
 

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