MHB Solving 3r(r+1)=r(r+1)(r+2)-r(r-1)(r+1) and Finding r(r+1) Sum

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To demonstrate that 3r(r+1) equals r(r+1)(r+2) - r(r-1)(r+1), expanding and factoring the right-hand side is essential. The discussion emphasizes the importance of recognizing that each 'r' term on the right is one less than the corresponding term on the left. Participants suggest using algebraic manipulation to simplify the equation effectively. The clarification about the approach to solving the problem highlights the nuances of "show that" questions in mathematics. Overall, the conversation revolves around algebraic techniques to prove the equality and find the sum of r(r+1).
Harry2
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Hey,
Please may someone help me.
How can I show that 3r(r+1) is equal to r(r+1)(r+2) - r(r-1)(r+1) and then I would find the total sum of r(r+1).
Thanks in advance for any help.
 
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Have you tried expanding r(r+1)(r+2) - r(r-1)(r+1)?

To find the sum, notice that each 'r' term on the right is 1 less than an 'r' term on the left.
 
To show:

$$3r(r+1)=r(r+1)(r+2) - r(r-1)(r+1)$$

try factoring the RHS. :)
 
MarkFL said:
To show:

$$3r(r+1)=r(r+1)(r+2) - r(r-1)(r+1)$$

try factoring the RHS. :)

I just thought you couldn't use the right hand side first because it was a show that question. Thanks both of you!
 
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