Solving a 100kg Trolley Uphill Problem: Can You Help?

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SUMMARY

The discussion focuses on solving a physics problem involving a 100kg trolley being pushed up a 30-degree incline. The key equations utilized include Newton's First and Second Laws, where the net force must equal zero for constant velocity and equal to 'ma' for acceleration. The correct force required to move the trolley at constant velocity is 600N, while the force needed to accelerate the trolley at 2m/s² is 800N. The participants emphasize the importance of correctly applying these fundamental principles to arrive at the right answers.

PREREQUISITES
  • Understanding of Newton's Laws of Motion
  • Basic knowledge of trigonometry, specifically sine functions
  • Ability to calculate net forces and acceleration
  • Familiarity with the concept of frictional forces
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  • Study the application of Newton's Laws in various scenarios
  • Learn how to resolve forces on inclined planes
  • Explore frictional force calculations in physics
  • Practice problems involving acceleration and net force calculations
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Students studying physics, educators teaching mechanics, and anyone interested in understanding forces on inclined planes.

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Homework Statement


!00kg trolley is being pushed up a rough 30 degree incline by a constant force F the firction force Ff between the incline and the trolley is 110n gravity is 9.8ms

Homework Equations


Determine the value of F that will move the trolley up the incline at a constant velocity
determine the value of F that will accelerate the trolley up the incline at a value of 2ms
calculate the acceleration if F=1000
what is the value of F if they trolley accelerates up the incline at 10ms

The Attempt at a Solution


Given this question at school have no formulas on how to do completely lost have spent 2 hours trying to find info on the net can't find anything
i attempted first question with mgxsin30* + 110 and got 600N and that was correct answer but i don't think i have the correct working out
and 2nd question i just did fnet = 100x2 600+200 = 800N and that was correct answer but I am pretty sure working out is wrong
 
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You have the correct answers, but please show how you arrived at them. For part a, since the movement is at constant velocity, there must be no net force acting in the direction of the incline (Newton 1, sum of all forces parallel to incline = 0). For part b, the net force acting in the direction of the incline must be equal to 'ma' (Newton 2, sum of all forces parallel to incline = ma).
 

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