How to Solve a Basic Sliding Box Problem on a Frictionless Ramp?

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Homework Help Overview

The discussion revolves around a physics problem involving a box being pushed up a frictionless ramp inclined at 28°. The original poster seeks to determine the magnitude of the applied horizontal force required to maintain constant speed.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to analyze the forces acting on the box, including the normal force and gravitational components. Some participants question the relationship between the forces and the geometry of the situation, particularly regarding the normal force and its relevance to the problem.

Discussion Status

Participants are exploring different interpretations of the forces involved. Some have provided calculations and reasoning, while others have confirmed similar findings. There is an acknowledgment that certain aspects, like the normal force, may not be essential to the problem's requirements.

Contextual Notes

There is mention of previous discussions on similar problems, indicating that this is a common topic in physics homework. The original poster expresses confusion about the relationships between the forces, suggesting a need for clarification on the setup and assumptions.

Brendan Webb
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Hi

A 90 kg box is pushed by a horizontal force F at constant speed up a ramp inclined at 28°, as shown. Determine the magnitude of the applied force.
  1. when the ramp is frictionless.

My attempt at a solution.

I diagrammed the problem as in the file uploaded. To figure out the horizontal force required to counter the force of the box sliding down the incline I figured that the horizontal force would have to be the hypotenuse because it needs to be stronger than both Fn and Fg(sin28). However, it shows the normal force being larger than Fg(sin28) in terms of side lengths when it should be the opposite way around. I am confused on how to solve this problem even though it has been posted before on this website. Any help would be much appreciated.

Thanks
Brendan
 

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Using a right angle calculator I came up with a more logical answer of 468 N. But that leaves the opposite side of my triangle at 220 N which I am not sure how I would get. Or would that 220 N be the Normal force pushing back against my horizontal force? If it is then I guess in this question it is inconsequential to know the normal force of the box against the ramp.
 
Brendan Webb said:
I guess in this question it is inconsequential to know the normal force of the box against the ramp.

Indeed. The component of F directed up the incline just needs to be equal and opposite to the force of gravity directed down the incline.
I got pretty much the same answer as you. Now, if they had asked for the normal force on the box...
 
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