Solving a Beam Question: 3000 kg, 6000 kg*m, Calculate Force & Tension

[afromanam]

ok, i don't know how to start this problem

the beam in the drawing weighs 3000 kg. It is attached to the wall by means of a simple union and without friction in point A. It is attached to the wall by means of a cable CD. The moment applied in point B is 6000 kg*m. Calculate graphically the force in point A and tension in cable CD:


lots of questions here:

0) when they say graphically... what exactly do the mean? you know, that you have to draw the lines with their exact length and their angle and with a ruler measure the resultant force...

1) UNITS: the kilograms here are kilograms force?, or should i convert them to Newtons?

2) REACTION IN POINT A: I assume there will be a reaction in the X and Y axis.

3) the main question here is: the momentum applied, how should i consider it when balancing the forces, does this thing have to do with flexural moments and that stuff? or i just translate the momentum applied to F*d?

thanks in advance for any help you can give me

 

[Pyrrhus]

Remember that unlike the force, that can only move along its line of action without doing a force-couple (force momentum) system, the momentum is a free vector and you can put it anywhere.

The momentum will only affect the sum of moments equation.

\sum \tau also represented as \sum M

Notice calculating sum of momentum on point B, won't make it 0 (It's a Free Vector).

 

[afromanam]

thanks a lot, i really appreciate it

and i really hope you're Somewhere in the Sunny Caribbean