Pin and cable supported by a beam

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SUMMARY

The discussion revolves around a physics problem involving a uniform beam supported by a pin and cable. Key parameters include a beam mass of 20.0 kg, two additional masses (M1 = 54.0 kg and M2 = 37.0 kg), lengths L1 = 2.90 m and L2 = 5.40 m, and an angle θ = 43.0°. Participants seek to determine the number of forces acting on the beam, the tension in the cable, and the horizontal and vertical components of the force exerted by the wall. The correct approach involves applying the principles of static equilibrium and summing moments about a pivot point.

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  • Understanding of static equilibrium principles
  • Knowledge of force decomposition (horizontal and vertical components)
  • Familiarity with tension calculations in physics
  • Ability to sum moments about a pivot point
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: Homework9-7
http://physci.kennesaw.edu/images/hm12-1.gif​
1. A uniform beam of mass m is supported in a horizontal position by a pin and cable as shown in the Figure. Given. m = 20.0 kg ; M1 = 54.0 kg ; M2 = 37.0 kg ; L1 = 2.90 m ; L2 = 5.40 m ; and θ = 43.0°.

a) How many forces are acting on the beam (treat the interaction at the pivot with the wall as 2 forces)?
RIGHT!

b) What is in N the tension of the cable?

c) What is in N, H, the horizontal component of the force exerted by the wall onto the beam? Assume the positive direction points towards the right.

d) What is in N, V, the vertical component of the force exerted by the wall onto the beam? Assume the positive direction points upwards.

Use 10.0 N/kg for g.

2. I believe to find tension I am using Ft=Fg x m x g but maybe I am using the wrong values?

3. I am honestly confused. I counted the forces and got that correct. I am unsure how to solve the other parts??
 
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What are the relevant equations?

Do you know how to sum moments about a point?
 

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