Solving a Calculus Equation with u and v Variables

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SUMMARY

The discussion centers on solving the calculus equation x∂f/∂x - 2y∂f/∂y = 6f(x,y) by changing variables to u and v, where u = α(x)y and v = y/x. Participants emphasize the importance of expressing the partial derivatives ∂f/∂x and ∂f/∂y in terms of u and v to facilitate finding the general solution. The method involves applying the chain rule and determining a suitable function α(x) to simplify the equation effectively.

PREREQUISITES
  • Understanding of partial derivatives
  • Familiarity with the chain rule in calculus
  • Knowledge of variable substitution techniques
  • Basic concepts of differential equations
NEXT STEPS
  • Study the application of the chain rule in multivariable calculus
  • Learn about variable substitution methods in differential equations
  • Explore the concept of homogeneous functions and their properties
  • Investigate the general solutions of first-order partial differential equations
USEFUL FOR

Students and educators in calculus, mathematicians focusing on differential equations, and anyone seeking to enhance their understanding of variable transformations in mathematical analysis.

implet
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Hi,

This is a question in my calculus book that is frustrating me!

By changing variables to u and v, where u=\alpha(x)y and v=y/x with a suitable function \alpha(x) to be determined, find the general solution of the equation x\frac{\partial f}{\partial x} - 2y\frac{\partial f}{\partial y}=6f(x,y).

I can see that the LHS of the equation looks similar to the chain rule, but I can't see how to continue...

Thanks :)
 
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HINT:

Can you write \partial f/\partial x and \partial f/\partial y in terms of [partial] derivatives with respect to u, v, x and y?
 

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