MHB Solving a definite integral without using gamma function

Click For Summary
The integral $$\int_0^{\infty} t^{-1/4}e^{-t}\,dt$$ cannot be evaluated using elementary methods and is represented by the gamma function as $\Gamma(3/4)$. While attempts were made to solve it through integration by parts, it was concluded that the gamma function is necessary for its evaluation. The discussion also touched on the formula $$\Gamma(x) \Gamma(1-x) = \pi \csc(\pi x)$$ and its application to products involving gamma values. A proof of this formula is complex, often requiring advanced techniques like complex analysis. Ultimately, the problem was resolved using the gamma function formula.
Saitama
Messages
4,244
Reaction score
93
Problem:
Evaluate:
$$\int_0^{\infty} t^{-1/4}e^{-t}\,dt$$

Attempt:
I recognised this one as $\Gamma(3/4)$. I found a few formulas on Wolfram Mathworld website which helps to evaluate this but I am wondering if I can solve the definite integral from elementary methods (like by parts).

Any help is appreciated. Thanks!
 
Physics news on Phys.org
This integral cannot be solved using elementary methods because the result is only representable using the gamma function

$$\Gamma(x) = \int^\infty_0 t^{x-1}\, e^{-t} \, dt$$

and cannot be introduced otherwise. The result can be written differently using some properties of the gamma function. For example ,

$$\Gamma(x) \Gamma(1-x) = \pi \csc(\pi x) $$

$$2^{1-2x}\sqrt{\pi}\Gamma(2x) = \Gamma\left( x+\frac{1}{2}\right) \Gamma(x) $$

$$\Gamma(1+x) = x \Gamma(x)$$
 
Thanks ZaidAlyafey! :)

Is there a proof for the following formula?

ZaidAlyafey said:
$$\Gamma(x) \Gamma(1-x) = \pi \csc(\pi x) $$

I am actually dealing with the product $\Gamma(3/4)\Gamma(1/2)\Gamma(1/4)$. If I use the above formula, I can easily find the value of the product.
 
This integral cannot be solved using elementary methods because the result is only representable using the gamma function

The proof is a pain. The one I saw used relatively large amount of differential galois applied to gamma values.
 
The proof that uses less formulas and easiest , in my opinion, is using complex analysis.
 
ZaidAlyafey said:
The proof that uses less formulas and easiest , in my opinion, is using complex analysis.

Its better that I stay away from the proof. :p

Thanks, I solved the problem using the formula. :)
 
Thread 'Problem with calculating projections of curl using rotation of contour'
Hello! I tried to calculate projections of curl using rotation of coordinate system but I encountered with following problem. Given: ##rot_xA=\frac{\partial A_z}{\partial y}-\frac{\partial A_y}{\partial z}=0## ##rot_yA=\frac{\partial A_x}{\partial z}-\frac{\partial A_z}{\partial x}=1## ##rot_zA=\frac{\partial A_y}{\partial x}-\frac{\partial A_x}{\partial y}=0## I rotated ##yz##-plane of this coordinate system by an angle ##45## degrees about ##x##-axis and used rotation matrix to...

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K