Solving a Diatomic Ideal Gas Problem: Find Temp & Energy Transfer

  • Thread starter Thread starter burgerkin
  • Start date Start date
Click For Summary

Homework Help Overview

The problem involves a diatomic ideal gas contained in a cylinder with a moving piston. The initial conditions include a specific volume and temperature, with the final volume being six times the initial volume. The tasks are to find the final temperature and the energy transfer by heat.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between pressure, volume, and temperature, and how these relate to the energy transfer and work done during the gas expansion. There are attempts to clarify the distinction between heat transfer and work done by the gas.

Discussion Status

Some participants have provided insights into the calculations and concepts involved, particularly regarding the work done by the gas and the implications of pressure being proportional to volume. There is ongoing exploration of how to accurately calculate work in this context.

Contextual Notes

Participants note confusion regarding the implications of pressure changes during the gas expansion and the need to account for external forces acting on the piston. There is a mention of the assumptions made about the system, such as the balance of pressures and the nature of the expansion.

burgerkin
Messages
35
Reaction score
0

Homework Statement



A cylindar w/ a moving piston holds 3.50 mol of a diatomic ideal gas. The initial vol. is Vi, and its temperature is Ti. Then the cylinder is set on a heat plate and additional weights are placed onto the piston as it moves up, and pressure is proportional to the volume and the final volume is 6Vi.

1, Find the final Temperature

2, find the energy transfer by heat

Homework Equations



pv =nRT

The Attempt at a Solution



I got the first part, the answer is Tf = 36 Ti

For second part, I thought it was straight forward, but the answer was wrong

I did :

Q=n Cv (Tf-Ti) = 3.5 x (5/2) R x 35 Ti =306.25 RTi

but the correct answer is 367.5 RTi

what did I do wrong?

Thanks!
 
Physics news on Phys.org
please help. thanks!
 
You forgot to account for the work done by the gas as it expanded. You correctly accounted for the internal energy change, but some of the energy went into lifting the weights.
 
oh i see. I was confused about heat and Q.

So the energy transfer by heat means the energy that caused the increase in temperature and the energy that the gas expands--work done by gas.

So E =Q +W
E=nCv\DeltaT

but how do I calculate Work? What kind of expansion is this. I see volume, pressure, temperature all change, so i do not know how to get work.
 
Read the problem: "pressure is proportional to the volume" How do you calculate the work of the gas?

ehild
 
W= -P(Vf-Vi) ?

i am not sure what does it imply" P is proportional to V..
 
I don't think I understand the physics of this well. sO THE presssure is the pressure of the gas? As it is heated up, it expands, then pressure should be decreasing, isn't it? But yet this is not a free expansion.
 
It is usually assumed that the pressure of the gas is balanced by the pressure of the external forces, here the atmospheric pressure and that of the weights put on the piston gradually. Work is

W=∫PdV from Vi to Vf and P=const*V.

ehild
 
press is proportional to volume
so let's ay press = k x vol
now work done is dw = (integral) p x dv
pure math actually not much physics
 

Similar threads

Replies
1
Views
2K
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
5
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K