- #1
magnifik
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Can someone help me find the solution for this
dy/dt = t/(y + 1) with initial condition y(2) = 0
here's what i have done so far
(y + 1) dy = t dt
y^{2}/2 + y = t^{2}/2 + C
i am confused on how to isolate y.
this is the solution
without using the initial condition. where did the + 1 in the square root and - 1 outside of the square root come from?
dy/dt = t/(y + 1) with initial condition y(2) = 0
here's what i have done so far
(y + 1) dy = t dt
y^{2}/2 + y = t^{2}/2 + C
i am confused on how to isolate y.
this is the solution