Solving a Difficult System of Equations in Dynamics

Click For Summary

Homework Help Overview

The discussion revolves around a system of equations related to a dynamics problem, involving variables such as a, b, v, x, and y, with equations that include trigonometric functions and a relationship between these variables. Participants are exploring the implications of having six equations for five unknowns and the potential inconsistencies within the system.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are attempting to clarify which quantities are variables versus constants, particularly questioning the status of v. There is discussion about the inconsistency of the equations and whether all can be correct. Some suggest using a coordinate system to visualize the problem, while others explore combining equations to derive new relationships.

Discussion Status

The conversation is ongoing, with some participants suggesting that the equations may be inconsistent, while others challenge this notion and propose alternative interpretations. There is a mix of exploratory reasoning and attempts to clarify the relationships between the equations.

Contextual Notes

Participants note the presence of an extra equation and the implications of having more equations than unknowns, which raises questions about the solvability of the system. There is also mention of the equations being in degrees, which may affect the interpretation of the trigonometric relationships.

74baja
Messages
3
Reaction score
0
Hi all,

I'm stuck on a system of equations I am left with at the end of a dynamics problem.

[itex] a=-b+v[/itex]
[itex] x=-b+vcos(30)[/itex]
[itex] y=vsin(30)[/itex]
[itex] 171.5=20b^2+5a^2[/itex]
[itex] a^2=x^2+y^2[/itex]
[itex] 10x-40b=0[/itex]
All in degrees.
I know I have an extra equation, but I thought I'd include it in case it is easier to solve with a certain five of them. I know it's not as simple as solving for one variable in terms of one other, plugging in and solving. I tried looking at it for ways to recombine the equations- no luck.

Thank you,
Jack
 
Physics news on Phys.org
74baja said:
Hi all,

I'm stuck on a system of equations I am left with at the end of a dynamics problem.

[itex] a=-b+v[/itex]
[itex] x=-b+vcos(30)[/itex]
[itex] y=vsin(30)[/itex]
[itex] 171.5=20b^2+5a^2[/itex]
[itex] a^2=x^2+y^2[/itex]
[itex] 10x-40b=0[/itex]
All in degrees.
I know I have an extra equation, but I thought I'd include it in case it is easier to solve with a certain five of them. I know it's not as simple as solving for one variable in terms of one other, plugging in and solving. I tried looking at it for ways to recombine the equations- no luck.

Thank you,
Jack

Could you clarify which quantities are variables, and which are constants? Is v a variable, for instance?
 
74baja said:
Hi all,

I'm stuck on a system of equations I am left with at the end of a dynamics problem.

[itex] a=-b+v[/itex]
[itex] x=-b+vcos(30)[/itex]
[itex] y=vsin(30)[/itex]
[itex] 171.5=20b^2+5a^2[/itex]
[itex] a^2=x^2+y^2[/itex]
[itex] 10x-40b=0[/itex]
All in degrees.
I know I have an extra equation, but I thought I'd include it in case it is easier to solve with a certain five of them. I know it's not as simple as solving for one variable in terms of one other, plugging in and solving. I tried looking at it for ways to recombine the equations- no luck.

Thank you,
Jack

You have 6 equations in 5 unknowns a, b, v, x, y, In this case, there is no solution: the equations are inconsistent.

If you leave out the fifth equation (##a^2 = x^2 + y^2##) you can fairly easily solve the remaining equations, just by expressing a,v,x,y in terms of b (using equations 1,2,3,6) and then finding b from equation 4. To see that the original system is inconsistent, just substitute the resulting solution into the missing equation 5.
 
I didn't really go into details to calculate the answer, and with 6 equations to find 5 variables it is more than enough and I assume that all equations are correct (i.e. either equation left out can provides same answer), let's use a coordinate system to solve this problem, plot x-y axis and for equation 5, a^2=x^2+y^2, it is a circle, from there you can easily get your answer.

Let's explain more, equation 2, x-b=vcos30, equation 3 y=vsin30, combine can get (x-b)^2+y^2=v^2, another circle, I think this can gives you a clear picture?
 
Last edited:
csleong said:
I didn't really go into details to calculate the answer, and with 6 equations to find 5 variables it is more than enough and I assume that all equations are correct (i.e. either equation left out can provides same answer), let's use a coordinate system to solve this problem, plot x-y axis and for equation 5, a^2=x^2+y^2, it is a circle, from there you can easily get your answer.

Let's explain more, equation 2, x-b=vcos30, equation 3 y=vsin30, combine can get (x-b)^2+y^2=v^2, another circle, I think this can gives you a clear picture?

Perhaps you did not read my reply: the equations are inconsistent, so they cannot all be correct.
 
Ray Vickson said:
Perhaps you did not read my reply: the equations are inconsistent, so they cannot all be correct.

I think you should really read what I wrote, equation 2 and 3 actually can combine to gives (x+b)^2+y^2=v^2. So there are 5 equations, 5 variables. I don't know where your inconsistent come from, and why they cannot be all correct.

Okay.. yeah previous one I wrote wrongly, it should be x+b instead of x-b.
 
a=−b+v (1)
x=−b+vcos30 (2)
y=vsin30 (3)
171.5=20b^2+5a^2 (4)
a^2=x^2+y^2 (5)
10x−40b=0 (6)

From equation 6 => x=4b (7)
From equation 2 => x+b=vcos30 (8)
square(equation 8) + square(equation 3) => (x+b)^2+y^2=v^2 (9)

Sub equation 7 to equation 9 => 25b^2+y^2=v^2 (10)
Sub equation 7 to equation 5 => 16b^2+y^2=a^2 (11)
equation 10 minus equation 11 => 9b^2=v^2-a^2 (12)

From equation 1 => v=a+b (13)
Sub equation 13 to equation 12 => 9b^2=(a+b)^2-a^2
8b^2-2ab=0
b=0 or a=4b

Okay I think Ray is right, my view of the "combining 2 equations" become a circle is a big mistake because of the angle of 30 degree, they are 2 linear equations and a combination of them can't make a circle.

Sorry for the stupid concept.
 
Last edited:

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
2
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 26 ·
Replies
26
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
Replies
6
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K