Solving a first order differential equation

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Homework Help Overview

The discussion revolves around solving a first-order differential equation represented by the equation (\frac{dr}{ds})^2+(\frac{l}{r})^2=1. Participants are exploring the relationship between the variables and attempting to derive the solution r=\sqrt{l^2+(s-s_0)^2}.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss rewriting the equation to isolate variables and explore the implications of the solution's form. There are attempts to separate variables and clarify the relationship between r and ds.

Discussion Status

The conversation is active, with participants providing guidance on how to manipulate the equation. Some have noted the connection to Pythagorean principles, while others are working through the separation of variables. There is a recognition of the challenge in rewriting the equation appropriately.

Contextual Notes

Some participants mention the difference between problems that provide a solution and those that require deriving one, indicating a potential misunderstanding of the problem type.

stephen cripps
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Homework Statement


We have the equation
## (\frac{dr}{ds})^2+(\frac{l}{r})^2=1 ##
and want to solve to get ## r=\sqrt{l^2+(s-s_0)^2}##

Homework Equations

The Attempt at a Solution


I have worked backwards, plugging in the solution to prove that it is correct, but the closest I have gotten to actually finding the solution without using r is: ##\frac{dr}{ds}=\frac{\sqrt{r^2-l^2}}{r}##

Can anyone help with where to go from here?
 
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What you have is a good start. Can you rewrite the equation just a little more so that only ## r ## and ## dr ## show up on one side and only ## ds ## shows up on the other?
 
Hello Stephen,

I take it you have seen the solution satisfies the differential equation ?

And doesn't the solution remind you of good old Pythagoras ?
 
stephen cripps said:

Homework Statement


We have the equation
## (\frac{dr}{ds})^2+(\frac{l}{r})^2=1 ##
and want to solve to get ## r=\sqrt{l^2+(s-s_0)^2}##

Homework Equations

The Attempt at a Solution


I have worked backwards, plugging in the solution to prove that it is correct, but the closest I have gotten to actually finding the solution without using r is: ##\frac{dr}{ds}=\frac{\sqrt{r^2-l^2}}{r}##

Can anyone help with where to go from here?
Some differential equation problems take the form of "show that this equation is a solution of the differential equation ..." Other differential equation problems ask you to solve a given DE, and don't provide the solution. Your problem appears to be the latter type.

To start, note that ## (\frac{dr}{ds})^2+(\frac{l}{r})^2=1 ## can be rewritten as ## \frac{dr}{ds} = \pm \sqrt{1 - (\frac{l}{r})^2} ##
 
Geofleur said:
What you have is a good start. Can you rewrite the equation just a little more so that only ## r ## and ## dr ## show up on one side and only ## ds ## shows up on the other?
This is the part of the problem I'm having trouble with
 
stephen cripps said:
This is the part of the problem I'm having trouble with
What is the trouble you're having?
Starting from ## \frac{dr}{ds} = \pm \sqrt{1 - (\frac{l}{r})^2} ##, separate the variables by dividing both sides by ##\sqrt{1 - (\frac{l}{r})^2} ##, and multiplying both sides by ds. You will need to handle the + and - cases with an equation for each.
 
Oh yeah, I have it now. I was being stupid.
 

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