Solving a Horizontally Oscillating Ball Problem

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Homework Help Overview

The problem involves a 130 g ball attached to a spring oscillating horizontally on a frictionless table, with specific parameters such as spring constant and velocity at a given position. The participants are tasked with finding the amplitude of oscillation, maximum acceleration, and speed at another position.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • One participant attempts to solve for amplitude by equating velocity and position equations but struggles with the phase shift. Another suggests using energy equations to find amplitude and discusses the conditions for maximum acceleration. There is also a discussion about the relationship between potential energy and maximum acceleration, with questions about the calculations involved.

Discussion Status

Participants are exploring different approaches to the problem, including energy methods and force equations. Some guidance has been offered regarding the use of energy conservation, but there is no explicit consensus on the best method to proceed. Questions remain about the calculations and assumptions being made.

Contextual Notes

Participants are navigating the complexities of the equations involved, including potential energy and force relationships, while also addressing the implications of phase shifts and maximum values in their reasoning.

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Homework Statement


A 130 g ball attached to a spring with spring constant 3.0 N/m oscillates horizontally on a frictionless table. Its velocity is 17 cm/s when x = 4.2 cm

Find the:
-Amplitude of Oscillation
-Max acceleration
-Speed of the ball when x = 2.8cm

Homework Equations


T = 2*pi*(m/k)1/2
Sinusoidal equations for position and velocity of a particle in SHM


The Attempt at a Solution



I'm not entirely sure where to start. I solved the velocity and position equations for t and set them equal to solve for A, but finding an intersection for that is beyond me. Not sure how else to work the equation.

I figured if I could find A then I could take the derivative of the velocity equation and try to solve for the maximum acceleration, but that still leaves the phase shift and doesn't give an acceleration value to set it equal to.

Not sure where to begin on this one at all.
 
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I think using energy equations is the easiest way to solve this. The total energy is given by 1/2kA^2 = 1/2kx^2 + 1/2mv^2

Solve for amplitude A.

As for the max acceleration, this will occur intuitively when all energy is potential and being converted into kinetic. Use F=ma whereF=-kx.

Hope that helps.
 
Last edited:
I hadn't thought about the energy perspective. Thanks for that one.

But about finding the max acceleration...

Since the potential of a spring is given by (1/2)(k)(x^2), I figure it was intuitive that the max acceleration would be when the spring is stretch to its max distance, its amplitude.

But (1/2)(3)(5.5^2) = (.13)(a) gives me a huge value for acceleration, which is being spit back. So I'm wondering what I'm missing. (yes, 5.5cm is the right amplitude).
 
I don't think I made myself clear before. I meant to solve the equation kx = ma (where x is the amplitude A) by equating forces. Your intuition is right, though.
 
Last edited:

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