Solving a Math Problem on Income with 5% Increases over 25 Years

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Homework Help Overview

The discussion revolves around a problem involving calculating total income over 25 years with annual increases of 5%. The original poster presents a scenario where an initial income of 5000 grows by 5% each year, leading to questions about the mathematical formulation of this growth.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the formula for calculating income increases, with some detailing the step-by-step multiplication of the initial income by 1.05 for each year. Questions arise regarding the constancy of the factor 1.05 and its derivation from the percentage increase.

Discussion Status

The discussion is active, with participants clarifying the mathematical reasoning behind the income growth formula. There is engagement in questioning the assumptions about the constancy of the growth factor and its origin, indicating a collaborative exploration of the topic.

Contextual Notes

Participants are navigating through the implications of a percentage increase and its representation in mathematical terms, with some expressing confusion about the foundational concepts involved in the problem.

darkmagic
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How do you solve this?
There is this kind of question in our test and I don't know how will I do it.

You're working in a company. Your starting income is 5000. Every year, the income will increase by 5%. What is your total income on your 25th year in the company?
 
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This is a question, not a tutorial so I am moving out of "Learning Materials" to "Precalculus Homework and School Work".

You startwith income at 5000 and it increases by 5% each year.

Okay, the first year your increases by "5% of 5000"= .05(5000)= 250 so your income the second year is 5250= 5000+ (.05)5000= (1.05)(5000). At the end of that year it increases by "5% of 5250"= .05(5250)= 262.50 and the third year your income is 5512.50= 5250+ (.05)5250= (1.05)(5250)= 1.05(1.05(5000)). The reason I wrote it out like that is because neither you nor I want to do that 24 times! (During your 25th year, your income will have increased 24 times.) You should be able to see what is happening: each year your income is multiplied by 1.05. After 24 years, that initial 5000 is multiplied by 1.05 24 times: [itex](1.05)^{24}(5000)[/itex].
 
[tex]a_1=5000[/tex]

[tex]a_2=a_1+a_1*\frac{5}{100}=a_1*1.05[/tex]

[tex]a_3=a_1*1.05 + a_1*1.05*0.05=a_1*1.05(1 + 0.05)=a_1*1.05*1.05[/tex]

[tex]a_4=a_1*1.05*1.05*1.05[/tex]

[tex].......[/tex]

[tex]a_{n+1}=a_1*(1.05)^{n}[/tex]

So a25=5000*(1.05)24

Regards.
 
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Is 1.05 constant?
 
darkmagic said:
Is 1.05 constant?

Yep, its a constant.
 
It's certainly not going to change!
 
ok. where is that 1.05 come from?
 
darkmagic said:
ok. where is that 1.05 come from?

If you see my way of solving the problem, you'll spot that

[tex]a_2=a_1+a_1*\frac{5}{100}=a_1(1+\frac{5}{100})=a_1\frac{100+5}{100}=a_1\frac{105}{100}=a_1*1.05[/tex]

See now where it comes from?
 
darkmagic said:
ok. where is that 1.05 come from?
I thought I had said that. Each year, your income is the same as the previous year (100%) and an additional 5% raise. Together that means your income each year is 105% of the previous year's. 105% is the same as 1.05.
 
  • #10
If it helps anyone, you can work this sort of thing out on Calcatraz, my new online calculator.

Just enter it as: http://www.calcatraz.com/calc?c=%245000+raised+by+5%25+in+year+25" , substituting your own values.
 
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