Solving a Problem with 2.55 eV/4.14 x 10^-15 eVs

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Homework Help Overview

The discussion revolves around a problem involving energy and frequency conversion, specifically relating to the calculation of frequency from energy values given in electron volts (eV). Participants are examining the relationship between the values provided and the resulting frequency expressed in hertz (Hz).

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning the transition from a negative exponent in the denominator to a positive exponent in the numerator. There is also an exploration of the division of the two energy values and its representation in scientific notation.

Discussion Status

The discussion is active, with participants sharing calculations and questioning the assumptions made in the problem. Some have provided calculations, while others are clarifying the implications of moving terms between the numerator and denominator.

Contextual Notes

Participants are working within the constraints of a textbook problem and are focused on understanding the mathematical relationships rather than deriving a final solution.

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Homework Statement



My book has a problem with a solution in which:

2.55 eV/4.14 x 10^-15 eVs = 6.16 x 10^ 14 Hz.

My question is:

I am trying to figure out why the answer is 10^14 when before they had 10^-15??
 
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domyy said:

Homework Statement



My book has a problem with a solution in which:

2.55 eV/4.14 x 10 to the power of -15 eVs = 6.16 x 10 the power of 14 Hz.

My question is:

I am trying to figure out why the answer is 10 to the power of 14 when before they had 10 to the power of -15??

What's 2.55/4.14? Express it in scientific notation.
 
2.55/4.14 = 0.616 approximately.
Then I say 6.16 x 10^-1
 
10^-1 x 10^-15 = 10^-16 not 10^14 as my book says.
 
domyy said:
2.55/4.14 = 0.616 approximately.
Then I say 6.16 x 10^-1
Correct.
domyy said:
10^-1 x 10^-15 = 10^-16 not 10^14 as my book says.
But the 10-15 is in the denominator. What happens to it when you 'promote' it to the numerator?
 
:smile::biggrin:ooooooooooooohhh I got it.
Thank you!:blushing:
 

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