Solving a pulley system (Dynamics)

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The discussion focuses on solving a dynamics problem involving a pulley system with a 100 kg crate and a 25 kg pulley. Participants emphasize the importance of correctly setting up the free body diagram, noting that the crate experiences a downward gravitational force and an upward tension force. Clarification is requested regarding the configuration of the ropes, particularly where the ends of the first rope are attached. The equations of motion are discussed, specifically the sum of forces in the vertical direction, leading to the equation T - mg = 0. The need for additional information to determine the tension in the rope connected to the ceiling is highlighted.
mmanor
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Solving a problem about a pulley system (dynamics)

A 100 kg crate is supported by a rope which passes over a 25 kg pulley. A 2nd rope connects the pulley to the ceiling. The system is stationary.

ƩFx=0 ƩFy=0

I am having problems setting up the free body diagram to start the problem!
 
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Where does the other end of the first rope go? Are both ends attached to the crate?
 
well using the information that you gave which is not very clear.

Your freebody diagram would be:

mg acting downward on the 1000kg block and Tension (T) acting upward on the block

Thats just for the block.


There are no foces acting in the X axis

ƩFy=o=T-mg (this is the sum of forces acting on the block)


Now the info that you gave in your original post was not very clear.. Please correct me if i missed anything and i will go back and make sure i correct everything.
 


You haven't stated what you are trying to find. It sounds like you want to find the tension in the rope connected to the ceiling. In that case you need a free body where that tension appears.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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