Solving a rational inequality with excluded endpoints

[ahbm]

Trying to get the last one, but not able to do it. What am I missing. I know that I can't but [-2,infinity] or [3,infinity] because for -2, and 3 y=0 and is not > 0. Any help appreciated.

 

[topsquark]

Is g(-2) > 0? No, so that part of the interval will be [math]( -\infty, -2)[/math].

-Dan

 

[HOI]

Also, because the question requires that f(x) be strictly less than 0, $$f(x)< 0$$ you cannot include x= -2 or x= 3. $$f(x)< 0$$ is true for $$(-\infty, -2)\cup (3, \infty)$$.