Solving a Toy Gyroscope Physics Problem: Mass, Moment of Inertia, and Precession

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    Gyroscope Physics
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Homework Help Overview

The problem involves a toy gyroscope, focusing on its mass, moment of inertia, and precession. Participants are tasked with determining the upward force exerted by the pivot and the angular speed of the rotor.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster seeks guidance on how to approach the problem step by step, indicating a lack of familiarity with gyroscopic concepts. Some participants provide calculations for part (a) and express uncertainty about part (b). Others share links to external resources that may assist in understanding the topic.

Discussion Status

The discussion includes attempts to calculate the upward force and ongoing work on the angular speed. While some calculations have been presented, there is no explicit consensus on the methods or solutions. Participants are exploring different aspects of the problem.

Contextual Notes

Participants are navigating the complexities of gyroscopic motion and may be working under constraints typical of homework assignments, such as needing to show their reasoning and calculations.

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Homework Statement



The rotor (flywheel) of a toy gyroscope has mass 0.140 kilograms. Its moment of inertia about its axis is 1.20 x10^-4 kilogram meters squared. The mass of the frame is 0.0250 kilograms. The gyroscope is supported on a single pivot with its center of mass a horizontal distance 4.00 centimeters from the pivot. The gyroscope is precessing in a horizontal plane at the rate of one revolution in 2.20 seconds.

(a) Find the upward force \vec{n} exerted by the pivot.

(b)Find the angular speed w at which the rotor is spinning about its axis, expressed in revolutions per minute.

Homework Equations



yf_Figure_10_49.jpg


\taunet = I*\alpha

F = ma

The Attempt at a Solution



I'm new to gyroscopes, so if anyone can point me in the right direction and help me step by step, that would be great!
 
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part (a) =

(m_gyro + m_frame)g = 1.617N

part(b)---working on it
 

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