Solving a Trigonometry Question: Rate of Change from pi to 11pi/6

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To find the rate of change of the function f(x) = tan x from pi to 11pi/6, the calculation involves determining the difference in x-values, which is expressed as 11pi/6 - pi. This simplifies to 11pi/6 - 6pi/6, resulting in 5pi/6. The gradient is then calculated using the formula (y1 - y0) / (x1 - x0), where the numerator represents the change in the function's values and the denominator is the change in x-values. Understanding this step is crucial for solving the problem correctly. The discussion emphasizes the importance of grasping basic fraction operations in trigonometric rate of change problems.
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Hey guys I am new in this forum so if i posted this question in the wrong section, please notify me. Anyway.
My concern here is this.

So I am trying to find the RATE OF CHANGE of f from pi to 11pi/6

f(x)= tan x

I have attached the part i need help on.
Note: This is very simple but there is one step which i don't understand.

The part where 11pi/6 - pi = 5pi/6 <----- How is this? Please explain...
thanks in advance.
 

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Don't you know how to add and subtract fractions?
 
the question is as good as asking you to find the gradient,

so the '11pi/6 - pi = 5pi/6' part is the x value of the gradient.,

similarly, the y value of the gradient is the top part as shown in your question

gradient is

y1 - y0
--------
x1 - x0
 
macdreboi said:
Hey guys I am new in this forum so if i posted this question in the wrong section, please notify me. Anyway.
My concern here is this.

So I am trying to find the RATE OF CHANGE of f from pi to 11pi/6

f(x)= tan x

I have attached the part i need help on.
Note: This is very simple but there is one step which i don't understand.

The part where 11pi/6 - pi = 5pi/6 <----- How is this? Please explain...
thanks in advance.
11pi/6- pi= pi(11/6- 1)= pi(11/6- 6/6).
 

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