Finding the Average Rate of Change for a Trig Function on a Given Interval

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SUMMARY

The average rate of change (AROC) of the function y = 2cos(x - π/3) + 1 over the interval π/2 < x < 5π/4 is calculated using the formula AROC = [f(x2) - f(x1)] / (x2 - x1). For this specific problem, x1 is π/2 and x2 is 5π/4. To find the exact AROC, evaluate the function at both endpoints: f(5π/4) and f(π/2), and substitute these values into the AROC formula.

PREREQUISITES
  • Understanding of trigonometric functions, specifically cosine.
  • Familiarity with radians and how to convert angles.
  • Knowledge of the average rate of change concept in calculus.
  • Ability to evaluate functions at specific points.
NEXT STEPS
  • Learn how to evaluate trigonometric functions at specific angles in radians.
  • Study the concept of limits and continuity in calculus.
  • Explore the application of the Mean Value Theorem in calculus.
  • Practice calculating average rates of change for various functions.
USEFUL FOR

Students studying calculus, particularly those focusing on trigonometric functions and their applications in finding rates of change.

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Homework Statement



Determine the average rate of change of the function y = 2cos (x - pi/3) + 1 for the following internal:
pi/2 < x < 5pi/4


Homework Equations


AROC = [ f(x2) - f(x1) ] / x2) - x1


The Attempt at a Solution



For an approx. value, I would set the calculator in radian mode and just plug everything into the equation, right?
Where I'm stuck is how to get an EXACT answer.
 
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If you're trying to find the average rate of change, I'm assuming that the interval would be pi/2 and 5pi/4 and those would be your x1 and x2 values.

To get an exact answer have to evaluate y at both your x1 and x2 values then fill out the slope equation:

{[2cos (5pi/4 - pi/3) + 1]*[2cos (pi/2 - pi/3) + 1]}/(5pi/4-pi/2)

Hope this helps
 

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