Solving absolute values of trigonometry

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SUMMARY

The discussion focuses on solving the equation 2sin(3x) = 1 and 2sin(3x) = -1, leading to sin(3x) = 1/2 and sin(3x) = -1/2. The key issue is determining the number of solutions for these equations within the interval of 0 to 3π. The correct number of solutions is identified as 6, not 3, due to the periodic nature of the sine function across the specified domain.

PREREQUISITES
  • Understanding of trigonometric functions, specifically sine.
  • Familiarity with the unit circle and its properties.
  • Knowledge of periodicity in trigonometric equations.
  • Ability to analyze graphs of trigonometric functions.
NEXT STEPS
  • Study the periodic properties of the sine function in detail.
  • Learn how to graph trigonometric functions and identify their intersections.
  • Explore the concept of inverse trigonometric functions and their applications.
  • Review solving trigonometric equations over specified intervals.
USEFUL FOR

Students studying trigonometry, educators teaching mathematical concepts, and anyone looking to enhance their problem-solving skills in trigonometric equations.

Physics53
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Homework Statement


math question.PNG


Homework Equations

The Attempt at a Solution


2sin3x=1 OR 2sin3x= -1
sin3x=1/2 sin3x= -1/2
From the unit circle and in accordance with the domain
there are 3 solutions (B)
But the answer is (C)
HOW?
 

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Physics53 said:

Homework Statement


View attachment 229661

Homework Equations

The Attempt at a Solution


2sin3x=1 OR 2sin3x= -1
sin3x=1/2 sin3x= -1/2
From the unit circle and in accordance with the domain
there are 3 solutions (B)
But the answer is (C)
HOW?
In your problem, ##\theta = 3x## runs from ##\theta = 0## to ##\theta = 3 \pi.## Look at a plot of ##y = \sin \theta## for ##0 \leq \theta \leq 3 \pi.## How many places are there at which ##\sin \theta = 1/2## or ##\theta = -1/2?##
 

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