The discussion centers on determining the cosine value for an angle where the tangent is given as -√3 and the angle lies in the third quadrant. The participants clarify that if tan(b) = -√3, then the angle b should be correctly identified as being in quadrant II or IV, not III. The sine value is calculated as sin(b) = -√3 / 2, leading to the conclusion that the cosine value, cos(b), is -1/2 based on the relationship cos = x/r, where x and r are derived from the coordinates in the unit circle.
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What does theta have to do with anything? Assuming that you meant b instead of theta, if tan(b) = -√3, then b is in quadrant II or quadrant IV.CrossFit415 said:How would I find cos for tan when..
Tan b = (-√3)
Theta lies in quadrant iii
CrossFit415 said:Sin b would equal (-√3) / 2
So Cos b would equal -1 / 2?