Solving Acceleration and Velocity Problems in the xy Plane

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A particle in the xy plane experiences constant acceleration, starting at position (7.0 m, 9.0 m) with an initial velocity of (5.0 m/s, -10.0 m/s) and an acceleration vector of (7.0 m/s², 0 m/s²). The user sought assistance in determining the velocity vector at 6 seconds and the position vector at 4 seconds. After some time, the user successfully solved the problem independently. The discussion highlights the importance of understanding kinematic equations for motion in two dimensions. Engaging with the problem ultimately led to a resolution.
dragonladies1
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I'm having trouble approaching this problem. I'm not sure how to set it up. Any help would be appreciated especially with necessary formulas and equations. Thank you.

A particle moves in the xy plane with constant acceleration. At time zero, the particle is at x = 7.0 m, y = 9.0 m, and has velocity v = 5.0 m/s + -10.0 m/s . The acceleration is given by the vector a = 7.0 m/s2 + 0 m/s2 .


I need to find the velocity vector at time= 6 seconds and position vector at 4 seconds. Thanks again.
 
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Thanks anyway, I figured it out.
 
You're welcome.

Congrats on taking action and re-approaching the problem.
 
What was the answer?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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