- #1
Victor23
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Can anyone please help me with this equation 3x =15
My workings ;3x=15
Any help is appreciated, thanks
= 5x, as 15 divide by 3x=5x
My workings ;3x=15
Any help is appreciated, thanks
= 5x, as 15 divide by 3x=5x
This makes no sense! In the first place, what does it mean to divide by an equation?Victor23 said:Can anyone please help me with this equation 3x =15
My workings ;3x=15
Any help is appreciated, thanks
= 5x, as 15 divide by 3x=5x
To solve an algebra equation with one variable, you need to isolate the variable on one side of the equation by using inverse operations. In the equation 3x=15, you can divide both sides by 3 to get x=5.
The order of operations in solving algebra equations is PEMDAS (Parentheses, Exponents, Multiplication and Division from left to right, Addition and Subtraction from left to right). This means you should first simplify any expressions within parentheses, then solve any exponents, followed by multiplication and division, and finally addition and subtraction.
Yes, you can always check your answer by plugging it back into the original equation. In the equation 3x=15, if you substitute x=5, you will get 3(5)=15, which is a true statement.
If an algebra equation has one variable and one solution, it will have a unique solution. However, if there are multiple variables or if the equation has an infinite number of solutions, it will have multiple solutions.
No, inverse operations are necessary to solve algebra equations. They allow you to isolate the variable and solve for its value. Without inverse operations, the equation would remain unsolved and the value of the variable would be unknown.