Solving algebraic equations with negative exponents

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To solve the equation x^-2 = 1/9, rewrite it as x^2 = 9, leading to x = ±3. For the equation x^-2 - 13x^-1 + 36 = 0, multiply through by x^2 to eliminate negative exponents, resulting in 1 - 13x + 36x^2 = 0. This simplifies to the quadratic equation 36x^2 - 13x + 1 = 0. The solutions can be found using the quadratic formula, yielding x values that can be calculated directly. Understanding the manipulation of exponents is crucial for solving these types of equations.
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solve for x: x^-2 = 1/9



solve for x: x^-2 - 13x^-1 +36 = 0



I don't understand how to solve either equations.
 
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Remember that x^{-a}=\frac{1}{x^a} so try multiplying through by x2 in both.
 

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