2. The attempt at a solution
(1/x-3)+(1/x+3)=(10/(x+3)(x-3)) - I factored the x^2-9 to make it easier to multiply by LCD.
x+3+x-3=10 - I multipled both sides by the LCD [(x+3)(x-3)]
2x=10 - Combined like terms
x=5 - Divided both sides by 2.
Am I wrong or is the book wrong for having the answer as x=2 ?