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## Homework Statement

(1/x-3)+(1/x+3)=(10/x²-9)

**2. The attempt at a solution**

(1/x-3)+(1/x+3)=(10/x²-9)

(1/x-3)+(1/x+3)=(10/(x+3)(x-3)) - I factored the x^2-9 to make it easier to multiply by LCD.

x+3+x-3=10 - I multipled both sides by the LCD [(x+3)(x-3)]

2x=10 - Combined like terms

x=5 - Divided both sides by 2.

Am I wrong or is the book wrong for having the answer as x=2 ?