Solving an equation involving sin and cos terms

  • Thread starter Thread starter nokia8650
  • Start date Start date
  • Tags Tags
    Cos Sin Terms
Click For Summary
SUMMARY

The discussion focuses on solving the equation 144 - 90sin x - 155.8cos x = 0 using a non-numerical approach. The solution involves rewriting the equation as 90sin x = 144 - 155.8cos x and then manipulating it to form a quadratic equation in terms of cos x. The derived quadratic equation is 8100(1 - cos² x) = 20736 - 44870.4cos x + 24273.64cos² x. The final step requires taking the arccosine of the solutions for cos x to find the corresponding values of x.

PREREQUISITES
  • Understanding of trigonometric identities, specifically sin and cos functions.
  • Knowledge of quadratic equations and their solutions.
  • Familiarity with algebraic manipulation techniques, including squaring both sides of an equation.
  • Ability to apply inverse trigonometric functions, such as arccosine.
NEXT STEPS
  • Study the derivation and properties of trigonometric identities.
  • Learn how to solve quadratic equations in various forms.
  • Explore the implications of squaring both sides of an equation and how it affects solutions.
  • Research the applications of inverse trigonometric functions in solving equations.
USEFUL FOR

Mathematics students, educators, and anyone interested in solving trigonometric equations without numerical methods.

nokia8650
Messages
216
Reaction score
0
Hi

I was wondering if there is a non-numericla way to solve the following equation:

144 - 90sin x - 155.8cos x = 0

Thanks
 
Physics news on Phys.org
nokia8650 said:
Hi

I was wondering if there is a non-numericla way to solve the following equation:

144 - 90sin x - 155.8cos x = 0

Thanks
That's not a nice equation but here's what I might do: write it as 90 sin x= 144- 155.8 cos x
90\sqrt{1- cos^2 x}= 144- 155.8 cos x and square both sides to get 8100(1- cos^2 x)= 20736- 44870.4cos x+ 24273.64cos^2 x. Solve that quadratic equation for cos x and then take the arccosine to find x. When you square both sides of an equation, that new equation may have roots that do not satisfy the original equation.
 
Thank you!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
4K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
989
  • · Replies 11 ·
Replies
11
Views
1K
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K