Solving an equation involving surds

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SUMMARY

The discussion focuses on solving the equation ##x^{1/6}=12x^{1/3}-1## and explores various algebraic techniques and substitutions, particularly using ##u=x^{1/6}##. Participants confirm that the equation can be transformed into a cubic form, leading to solutions such as ##u=2##, which corresponds to ##x=64##. The conversation emphasizes the importance of verifying solutions against the original equation and discusses the limitations of finding closed-form solutions for polynomials of degree greater than four, suggesting numerical methods for such cases.

PREREQUISITES
  • Understanding of algebraic equations and surds
  • Familiarity with polynomial equations and their degrees
  • Knowledge of substitution methods in algebra
  • Basic concepts of numerical methods for approximating solutions
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  • Research the general solution formulas for cubic equations
  • Explore numerical methods for solving higher-degree polynomial equations
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Mathematicians, algebra students, and anyone interested in solving complex equations involving surds and polynomial expressions.

  • #61
fresh_42 said:
Yes, and ##12=12\cdot 1 = 6 \cdot 2 = 4 \cdot 3##. Which one do we get for ##u##?
sorry for not seeing then, ...##u=2##
 
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  • #62
@chawala
Thanks for the explanation.
 

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