Solving an Odd Equation: Two Different x Values for Same F?

  • Context: Undergrad 
  • Thread starter Thread starter eahaidar
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Discussion Overview

The discussion revolves around solving the equation F(x) = Ax / (bx² + c) = constant, which is described as an odd function. The participant expresses confusion about obtaining two different x values for the same F, particularly questioning why the solutions are not simply the same positive and negative values.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant seeks to understand why solving the equation yields two different x values for the same F, despite the expectation of obtaining opposite values due to the function's odd nature.
  • Another participant clarifies that the constants involved should be treated as fixed values, suggesting that the equation can be rearranged into a quadratic form.
  • A further response indicates that the quadratic equation derived from the original function leads to two possible solutions for x, which may be perceived as problematic by the original poster.
  • There is a suggestion to graph the function to visualize its behavior, which may help in understanding the relationship between x and F.

Areas of Agreement / Disagreement

Participants appear to have differing views on the implications of obtaining two values for x. While some acknowledge that this is a standard outcome for quadratic equations, the original poster remains uncertain about the nature of these solutions.

Contextual Notes

The discussion includes assumptions about the constants involved and the treatment of x as a variable. There is also an unresolved aspect regarding the specific values of a, b, and c and how they influence the solutions.

eahaidar
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Hello everyone
I want to solve this equation
F(x)=Ax/((bx*x)+c =constant which is an odd function in which we get same positive and negative solutions for each F
But If I solve his equation I get two different x values for The same F any suggestions??
Thank you
 
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eahaidar said:
Hello everyone
I want to solve this equation
F(x)=Ax/((bx*x)+c =constant which is an odd function in which we get same positive and negative solutions for each F
But If I solve his equation I get two different x values for The same F any suggestions??
Do you mean two different x values for the same value of what you're calling the constant?

Graph y = x/(x^2 + 1) to get an idea of what your function F looks like.
 
First thank you for the reply
Second yes these are all constants but what I am asking about is how come if I solve it analytically I would not get 2 values on x same but opposite to each other
But different values of x
 
yes these are all constants
... surely you are treating x as a variable?
You seem to be wanting to solve: $$a=\frac{x}{bx^2+c}$$... here a=<constant>/A which is also a constant.

This becomes ##abx^2-x+ac = 0## which is a quadratic equation.

You are getting two possible values of x for given values of a,b, and c because there are two possible values that make the relation true. What is the problem?

Your concern seems to be that you are getting ##\pm## <the same number> as the roots ... if so, then please show your working.
 
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